x^4/3-9x^2/3+18=0

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Solution for x^4/3-9x^2/3+18=0 equation: 


x in (-oo:+oo)

(x^4)/3-((9*x^2)/3)+18 = 0

(x^4)/3-3*x^2+18 = 0

1/3*x^4-3*x^2+18 = 0

t_1 = x^2

1/3*t_1^2-3*t_1^1+18 = 0

1/3*t_1^2-3*t_1+18 = 0

DELTA = (-3)^2-(1/3*4*18)

DELTA = -15

DELTA < 0

x belongs to the empty set

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